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customer/supplier address deletion fix

develop
Ravi Dey 13 years ago
parent
commit
39f8c3cefe
  1. 11
      crm/doctype/customer/customer.py
  2. 12
      srm/doctype/supplier/supplier.py

11
crm/doctype/customer/customer.py

@ -214,8 +214,17 @@ class DocType:
#create address and contact from lead
self.create_lead_address_contact()
def delete_customer_address(self):
for rec in sql("select * from `tabAddress` where customer='%s'" %(self.doc.name), as_dict=1):
sql("delete from `tabAddress` where name=%s",(rec['name']))
def delete_customer_contact(self):
for rec in sql("select * from `tabContact` where customer='%s'" %(self.doc.name), as_dict=1):
sql("delete from `tabContact` where name=%s",(rec['name']))
# ******************************************************* on trash *********************************************************
def on_trash(self):
def on_trash(self):
self.delete_customer_address()
self.delete_customer_contact()
if self.doc.lead_name:
sql("update `tabLead` set status='Interested' where name=%s",self.doc.lead_name)

12
srm/doctype/supplier/supplier.py

@ -134,3 +134,15 @@ class DocType:
return contact_details
else:
return ''
def delete_supplier_address(self):
for rec in sql("select * from `tabAddress` where supplier='%s'" %(self.doc.name), as_dict=1):
sql("delete from `tabAddress` where name=%s",(rec['name']))
def delete_supplier_contact(self):
for rec in sql("select * from `tabContact` where supplier='%s'" %(self.doc.name), as_dict=1):
sql("delete from `tabContact` where name=%s",(rec['name']))
def on_trash(self):
self.delete_supplier_address()
self.delete_supplier_contact()

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